28=t^2/2-t/2

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Solution for 28=t^2/2-t/2 equation: 


t in (-oo:+oo)

28 = (t^2)/2-(t/2) // - (t^2)/2-(t/2)

t/2-((t^2)/2)+28 = 0

1/2*t-1/2*t^2+28 = 0

DELTA = (1/2)^2-(-1/2*4*28)

DELTA = 225/4

DELTA > 0

t = ((225/4)^(1/2)-1/2)/(-1/2*2) or t = (-(225/4)^(1/2)-1/2)/(-1/2*2)

t = -7 or t = 8

t in { -7, 8 }

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